2*cos^2(2*x)-sin(3*x)=3

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Solution for 2*cos^2(2*x)-sin(3*x)=3 equation:


Simplifying
2cos2(2x) + -1sin(3x) = 3

Remove parenthesis around (2x)
2cos2 * 2x + -1sin(3x) = 3

Reorder the terms for easier multiplication:
2 * 2cos2 * x + -1sin(3x) = 3

Multiply 2 * 2
4cos2 * x + -1sin(3x) = 3

Multiply cos2 * x
4cos2x + -1sin(3x) = 3

Remove parenthesis around (3x)
4cos2x + -1ins * 3x = 3

Reorder the terms for easier multiplication:
4cos2x + -1 * 3ins * x = 3

Multiply -1 * 3
4cos2x + -3ins * x = 3

Multiply ins * x
4cos2x + -3insx = 3

Solving
4cos2x + -3insx = 3

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '3insx' to each side of the equation.
4cos2x + -3insx + 3insx = 3 + 3insx

Combine like terms: -3insx + 3insx = 0
4cos2x + 0 = 3 + 3insx
4cos2x = 3 + 3insx

Divide each side by '4os2x'.
c = 0.75o-1s-2x-1 + 0.75ino-1s-1

Simplifying
c = 0.75o-1s-2x-1 + 0.75ino-1s-1

Reorder the terms:
c = 0.75ino-1s-1 + 0.75o-1s-2x-1

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